Since the car accelerates from rest so the initial velocity is zero
By using the law of motion and substituting the values given we get
v=u+at
180×518msec=0+a×25sec
On solving we get the acceleration as
a=2msec2
The distance covered by the car in this time interval is given as
S=ut+12at2
S=12(2)×(25)2=625m
Hence the distance travelled is 0.625km