A car acceleration from rest with $2 m / s^{2}$ on a straight line path and then comes to rest after applying brakes. Total distance travelled by the car is $100 m$ in $20$ seconds. The the maximum velocity attained by the car is

10 m / s

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20 m / s

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15 m / s

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5 m / s

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Solution

The correct option is A $10 m / s$
Distance traveled by car after applying brakes $S = 100 m$
Time taken to stop $t = 20 s$
Final speed of car $v = 0$
Let the initial maximum speed of the car be $u$ .
Using $v = u - a t$
where $a$ is the deceleration of car.
$∴$ $0 = u - a (20)$
$⟹ u = 20 a$ ....(1)
Using $v^{2} - u^{2} = 2 (- a) S$
$∴$ $0 - (20 a)^{2} = 2 (- a) (100)$
$⟹ a = 0.5$
From (1), we get $u = 20 \times 0.5 = 10 m / s$

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A car acceleration from rest with 2m/s2 on a straight line path and then comes to rest after applying brakes. Total distance travelled by the car is 100m in 20 seconds. The the maximum velocity attained by the car is

A car acceleration from rest with $2 m / s^{2}$ on a straight line path and then comes to rest after applying brakes. Total distance travelled by the car is $100 m$ in $20$ seconds. The the maximum velocity attained by the car is