A car and a truck are moving with the same velocity of $60 k m / h$ . Which one has more kinetic energy ? $(M_{T} > M_{C})$ .

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Solution

We know, $K . E = \frac{1}{2} M V^{2}$

$V_{T} = V_{C} = 60 k m / h r$
$∵ M_{T} > M_{C} ⟹ K . E_{T} > K . E_{C}$
Hence, truck has more kinetic energy.

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A car and a truck are moving with the same velocity of 60 km/h. Which one has more kinetic energy ?(MT>MC).

We know, K.E=12MV2VT=VC=60 km/hr∵MT>MC⟹K.ET>K.ECHence, truck has more kinetic energy.

A car and a truck are moving with the same velocity of $60 k m / h$ . Which one has more kinetic energy ? $(M_{T} > M_{C})$ .

We know, $K . E = \frac{1}{2} M V^{2}$

$V_{T} = V_{C} = 60 k m / h r$
$∵ M_{T} > M_{C} ⟹ K . E_{T} > K . E_{C}$
Hence, truck has more kinetic energy.