A car aquires a velocity of $72 k m / h$ in $10 s e c$ . starting from lust. Find (a) The acceleration (b) the average velocity (c) the distance travelled in this time.

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Solution

Initial Velocity = u = 0

Final velocity = v = 72 $k m / h r$

= 72 $\times \frac{5}{18}$ = 20 $m / s$

Time = t = 10 sec

Acceleration = a

Equation of motion :-

v = u + at

20 = 0 + 10a

a = $\frac{20}{10}$

a = 2 $m / s^{2}$

displacement = distance traveled = s

Equation of motion :-

$v^{2} - u^{2}$ = 2as

$20^{2} = 2 \times 2 \times s$

400 = 4s

s = $\frac{400}{4}$

s = 100 m

Average velocity = $\frac{d i s p l a c e m e n t}{t i m e}$

= $\frac{100}{10}$

= 10 $m / s$

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A car aquires a velocity of 72 km/h in 10 sec. starting from lust. Find (a) The acceleration (b) the average velocity (c) the distance travelled in this time.

A car aquires a velocity of $72 k m / h$ in $10 s e c$ . starting from lust. Find (a) The acceleration (b) the average velocity (c) the distance travelled in this time.