Question

A car at rest starts moving with uniform acceleration of $10m{s}^{-2}$ for a time of 10 seconds. What is the distance covered by the car?

• A. 100 m
• B. 500 m
• C. 200 m
• D. 600 m

Answer 1

The correct option is B 500 m

Given, initial velocity, u = 0 ( the car is initially at rest)
time taken, $t=10s$
acceleration, $a=10m{s}^{-2}$

Let the distance covered be '$s$'.

From the second equation of motion,
$s=ut+\frac{1}{2}\times {at}^2$
$s=(0\times 10)+(\frac{1}{2}\times 10\times {10}^2)$
$\Rightarrow s=\frac{1000}{2}$ = $500m$
$\therefore$The distance covered by the car is 500 m.