A car battery with a 12V emf and an internal resistance of 0.04Ω is being charged with a current of 50A.The potential difference V across the terminals of the battery is:
A
10V
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B
12V
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C
14V
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D
16V
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Solution
The correct option is C14V Given,
ε=12V
r=0.04Ω
I=50A
The potential Difference across the terminal is V
V=IR
Here,
I=ER+r
I(R+r)=E
IR+Ir=E
Substitute V=IR in above equation
V+Ir=E
V=E−Ir
As Battery is charging then current direction will be reverse Therefore,