A car changes its speed from $20 k m h^{- 1}$ to $50 k m h^{- 1}$ of mass $3600 k g$ in $5 s$ . Determine the net external force applied on the car.

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Solution

Step 1: Given data
$M a s s (m) = 3600 k g I n i t i a l v e l o c i t y (u) = 20 k m h^{- 1} F i n a l v e l o c i t y (v) = 50 k m h^{- 1} T i m e (t) = 5 s$
Step 2: Finding the net external force applied on the car
$F = m a = m \times (\frac{v - u}{t}) F = 3600 \times (\frac{50 - 20}{5}) \times \frac{5}{18} F = 3600 \times (\frac{30}{5}) \times \frac{5}{18} F = 3600 \times \frac{30}{18} F = 6000 N$
Thus, the net external force applied on the car is $6000 N$ .

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A car changes its speed from 20kmh-1 to 50kmh-1 of mass 3600kg in 5s. Determine the net external force applied on the car.

Step 1: Given dataMass(m)=3600kgInitialvelocity(u)=20kmh-1Finalvelocity(v)=50kmh-1Time(t)=5sStep 2: Finding the net external force applied on the carF=ma=m×v-utF=3600×50-205×518F=3600×305×518F=3600×3018F=6000NThus, the net external force applied on the car is 6000N.

A car changes its speed from $20 k m h^{- 1}$ to $50 k m h^{- 1}$ of mass $3600 k g$ in $5 s$ . Determine the net external force applied on the car.