A car completes the journey from A to B at a constant speed of 20km/hr and covers the return journey from B to A at a constant speed of 30km/hr. The average speed for the total journey from A to B and back is
Let the distance, AB=S
Speed for journey A→B is v1=20 km/hr
Speed for journey B→A is v2=30 km/hr
Time for distance S will be t=distancespeed
Time for journey A→B is t1=Sv1=S20
Time for journey B→A is t2=Sv2=S30
Total distance for A→B then B→B is
=AB+BA=S+S=2S
Total time for A→B then B→B is
=t1+t2
So average speed =Total distanceTotal time=2St1+t2
=2S(S20+S30)
=2S×20×30S×50
=24 km/hr