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Question

A car completes the journey from A to B at a constant speed of 20km/hr and covers the return journey from B to A at a constant speed of 30km/hr. The average speed for the total journey from A to B and back is

A
24km/hr
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B
600km/hr
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C
25km/hr
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D
50km/hr
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Solution

The correct option is A 24km/hr

Let the distance, AB=S

Speed for journey AB is v1=20 km/hr

Speed for journey BA is v2=30 km/hr


Time for distance S will be t=distancespeed

Time for journey AB is t1=Sv1=S20

Time for journey BA is t2=Sv2=S30


Total distance for AB then BB is

=AB+BA=S+S=2S

Total time for AB then BB is

=t1+t2


So average speed =Total distanceTotal time=2St1+t2

=2S(S20+S30)

=2S×20×30S×50

=24 km/hr


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