Question

A car contains three seats, one in front for driver and two in the rear. If seven persons are available in which only two can drive, then number of ways in which car can be filled is-

• A. 10
• B. 20
• C. 40
• D. 60

Answer 1

Answer: (D)

60

Total no. of person $=7$

Total no. of persons who can drive $=2$

No. of ways in which the driver seat can be filled $=2!$

Now, no. of persons left after filling the driver seat $=6$

No. of ways in which the remaining seats can be filled $={}^6{P}_2$

Therefore,

No. of ways in which car can be filled $=2!\times {}^6{P}_2=60$

Hence the number of ways in which car can be filled is $60$.