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2nd Equation of Motion

A car covers ...

Question

A car covers 90 km in $1 \frac{1}{2}$ hours towards east. Calculate (i) displacement of car, (ii) its velocity in (a) $k m h^{- 1}$ (b) $m s^{- 1}$

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Solution

$d i s p l a c e m e n t = 90 k m$ in east direction

$v e l o c i t y = \frac{d i s p l a c e m e n t}{t i m e} = \frac{90}{1.5} = 60 k m / h$ along east

$60 k m / h = 60 \times \frac{5}{18} = 16.67 m / s$

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