Question

A car covers a certain distance in $25$ hrs. if its reduces the speed by $\frac{1}{5}$th , the car covers $200km$ less in that time . the speed of car is

• A. $60km/hr$
• B. $30km/hr$
• C. $40km/hr$
• D. $50km/hr$

Answer 1

Answer: (C)

$40km/hr$

Let the initial speed of car $=xkm/hr$

$t=25hr$

Initially, total distance covered by car $=25\times x=25xkm$

Since, the speed of car is reduced by $\frac{1}{5}th$.

So, the new speed of car $=x-\frac{x}{5}=\frac{4x}{5}km/hr$

According to the question,

$25\times \frac{4x}{5}=25x-200$

$20x=25x-200$

$5x=200$

$x=40km/hr$

Hence, this is the answer.