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Question

A car covers a distance of 250 m in 6 seconds. If the acceleration of the car is 6 ms−2. Find the final velocity of the car.

A
79.66 ms1
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B
59.66 ms1
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C
69.66 ms1
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D
49.66 ms1
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Solution

The correct option is B 59.66 ms1
Given,
distance covered, s = 250 m,
time taken, t = 6 s
acceleration, a = 6 ms2

Let the initial velocity of the car be u and final velocity be v.
From the second equation of motion,
s=ut+12×at2
250=u×6+12×6×62
u=23.66 ms1
From the first equation of motion,
v = u + at
v=23.66+6×6 = 59.66 ms1
The final velocity of the car is 59.66 ms1

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