1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard VIII
Physics
Acceleration
A car deceler...
Question
A car decelerates from a speed of 20 m/s to rest in a distance of 100 m .What was its acceleration ,assume constant ?
Open in App
Solution
u
=
20
m
/
s
v
=
0
s
=
100
m
v
2
-
u
2
=
2
a
s
0
-
400
=
2
×
a
×
100
a
=
-
2
m
/
s
2
Suggest Corrections
0
Similar questions
Q.
A car starting from rest, accelerates at a constant rate
α
for some time after which it decelerates at a constant rate
β
to come to rest. If the total time of travel is
t
, find the total distance travelled by it assuming it to travel in a straight line.
Q.
A car accelerates from rest at a constant rate
α
for some time after which it decelerates at a constant rate
β
to come to rest. If the total time elapsed is t then, the distance travelled by the car is
Q.
A car moving with constant acceleration covered the distance between two points
60.0
m
apart in
6.00
s
. Its speed as it passes the second point was
15.0
m
/
s
. At what prior distance from the first was the car at rest?
Q.
A car starts from rest and moves with uniform acceleration a on a straight road from time t = 0 to t = T. After that, a constant deceleration brings it to rest. In this process the average speed of the car is
Q.
A car starts from rest and moves with uniform acceleration
a
on a straight road from time
t
=
0
t
o
t
=
T
. After that, a constant deceleration brings it to rest. In this process the average speed of the car is
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Acceleration & Retardation
PHYSICS
Watch in App
Explore more
Acceleration
Standard VIII Physics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Solve
Textbooks
Question Papers
Install app