The correct option is A -1.11 ms−2
Given, initial velocity, u=80 kmph=80×518=22.22 ms−1
final velocity, v=60 kmph=60×518=16.67 ms−1
and time taken, t = 5 s
Let 'a' be the acceleration of the car.
We know from first equation of motion, v=u+at
∴ a=v − ut
⇒a=16.67 − 22.225
⇒a=−1.11 ms−2
∴ Acceleration of the car is −1.11 ms−2
Note: Negative sign show that the car is decelerating.