A car driver covers a distance of 78 km in 1.5 hrs by moving at a speed of x kmph for the first 30 min, then moving at double the speed for the next 40 mins, and then again moving at his original speed for the rest of the journey. What is the value of x?

26 kmph

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36 kmph

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46 kmph

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56kmph

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66 kmph

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Solution

The correct option is B
36 kmph

Total distance = 78 km

Total time = 90 min

D = S $\times$ T

x $\times$ $\frac{30}{60}$ + 2x $\times$ $\frac{40}{60}$ + x $\times$ $\frac{20}{60}$ = 78 km

x = 36 kmph

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A car driver covers a distance of 78 km in 1.5 hrs by moving at a speed of x kmph for the first 30 min, then moving at double the speed for the next 40 mins, and then again moving at his original speed for the rest of the journey. What is the value of x?

The correct option is B 36 kmph Total distance = 78 km Total time = 90 min D = S×T x × 3060 + 2x × 4060 + x × 2060 = 78 km x = 36 kmph

The correct option is B
36 kmph

Total distance = 78 km

Total time = 90 min

D = S $\times$ T

x $\times$ $\frac{30}{60}$ + 2x $\times$ $\frac{40}{60}$ + x $\times$ $\frac{20}{60}$ = 78 km

x = 36 kmph