CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A car driving at a constant speed of 25 m/s, heads straight to a mountain. The driver presses the car horn and recieves an echo 3.6 seconds later. Calculate the distance between the car and the mountain when the driver pressed the horn.

(An echo is a repeated sound that is caused by the reflection of the sound waves from the surface. Take the speed of sound in air to be 300 m/s. )

A
1080 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
90 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
585 m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
495 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 585 m
Given,
Speed of the car, S = 25 m/s
Speed of the sound in air, V = 300 m/s
Time taken to receive the echo, T = 3.6 s

Let the distance between the car and the mountain when the driver pressed the horn be X.
Let the distance between the car and the mountain when the driver recieved the echo be Y.


After 3.6 seconds, the distance travelled by the car = X - Y
Therefore, X - Y = S × T
= 25 × 3.6 = 90 m ...............(i)
Distance travelled by the sound wave from the horn pressed till the echo recieved by the driver = X + Y
Therefore, X + Y = V × T
= 300 × 3.6 = 1080 m .................(ii)

From (i) and (ii),
X - Y = 90
X + Y = 1080
Therefore, by solving (i) and (ii),
2X = 1170
X = 585

Hence, the distance between the car and the mountain when the driver pressed the horn is 585 m.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Sound needs a medium for propagation
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon