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Question

A car falls off a ledge and drops to the ground in 0.5s(g=10ms2). calculate:

How high is the ledge from the ground?
What is its speed on striking the ground?
What is its average speed during 0.5 s?

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Solution

Time of free fall,

s=ut+12at2

initial velocity is 0 so

h=12gt2=1210×0.52=1.25m

(c) height from ground is 1.25m

Apply kinematic equation of motion

v2u2=2as

v=2gh=2×10×1.25=5ms1

(a)Speed of car striking the ground is 5ms1

(b)Average speed, vavg=v0h=51.25=4ms1


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