A car goes on horizontal circular road of radius $4$ m. The speed of car is increasing at a constant $3 m / s^{2}$ . The friction coefficient between road and tyre is $0.5$ . Find the speed at which the car will skid.

1

m/s

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2.5

m/s

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3.7

m/s

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4.4

m/s

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Solution

The correct option is A $1$ m/s
Radius, $r = 4$ $m$
Coefficient of friction, $μ = 0.5$
Maximum speed, $V_{m a x} = \sqrt{μ r g}$
$⟹ V_{m a x} = \sqrt{0.5 \times 4 \times 9.8}$
$⟹ V_{m a x} = 4.427$ $m / s$
Therefore, the car will skid after it exceeds $4.427$ $m / s$ of speed.

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A car goes on horizontal circular road of radius 4m. The speed of car is increasing at a constant 3m/s2. The friction coefficient between road and tyre is 0.5. Find the speed at which the car will skid.

The correct option is A 1m/sRadius, r=4 mCoefficient of friction, μ=0.5Maximum speed, Vmax=√μrg⟹Vmax=√0.5×4×9.8⟹Vmax=4.427 m/sTherefore, the car will skid after it exceeds 4.427 m/s of speed.

A car goes on horizontal circular road of radius $4$ m. The speed of car is increasing at a constant $3 m / s^{2}$ . The friction coefficient between road and tyre is $0.5$ . Find the speed at which the car will skid.

The correct option is A $1$ m/s
Radius, $r = 4$ $m$
Coefficient of friction, $μ = 0.5$
Maximum speed, $V_{m a x} = \sqrt{μ r g}$
$⟹ V_{m a x} = \sqrt{0.5 \times 4 \times 9.8}$
$⟹ V_{m a x} = 4.427$ $m / s$
Therefore, the car will skid after it exceeds $4.427$ $m / s$ of speed.