A car has a fresh storage battery of EMF 12 V and internal resistance 5 - 10-2 - If the starter motor draw electric current of 90 A what is the terminal voltage of battery when the starter is on -

The relationship between the terminal voltage #10;and emf is given as #10; #10; V = #10;ε #160; Ir #10; #10; V = 12 #10;( 90 × 5 × ...

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Byju's Answer

Standard XII

Physics

EMF and EMF Devices

A car has a f...

Question

A car has a fresh storage battery of $E M F$ $12 V$ and internal resistance $5 \times 10^{- 2} .$ If the starter motor draw electric current of $90 A$ what is the terminal voltage of battery when the starter is on ?

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Solution

The relationship between the terminal voltage and emf is given as

$V = ε - I r$

$V = 12 - (90 \times 5 \times 10^{- 2})$

$V = 7.5 V$

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A car has a fresh storage battery of EMF 12V and internal resistance 5×10−2. If the starter motor draw electric current of 90A what is the terminal voltage of battery when the starter is on ?

The relationship between the terminal voltage and emf is given as V=ε−Ir V=12−(90×5×10−2) V=7.5V

A car has a fresh storage battery of $E M F$ $12 V$ and internal resistance $5 \times 10^{- 2} .$ If the starter motor draw electric current of $90 A$ what is the terminal voltage of battery when the starter is on ?

The relationship between the terminal voltage and emf is given as

$V = ε - I r$

$V = 12 - (90 \times 5 \times 10^{- 2})$

$V = 7.5 V$