A car increases its speed from $20 k m / h$ to $50 k m / h$ in 10 seconds. Its acceleration is

30 m s^{- 2}

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3 m s^{- 2}

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18 m s^{- 2}

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None of these

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Solution

The correct option is D None of these
Acceleration is change in velocity per unit time

$a = \frac{(v_{2} - v_{1})}{(t_{2} - t_{1})}$

$v_{2} - v_{1} = 30 k m p h$ = $30 \times (5 / 18) m / s$

$= \frac{25}{3} m / s$

$t_{2} - t_{1} = 10 s$

$a = \frac{25}{(3 \times 10)} = \frac{5}{6} m / s^{2}$

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