A car initially at rest starts moving with a constant acceleration of $0.5 m s^{- 2}$ and travels a distance of $25 m$ . Find the final velocity.

4 m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 m s^{- 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

6 m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6.5 m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $5 m s^{- 1}$
Given,
$u = 0$
$a = 0.5 m s^{- 2}$
$s = 25 m$

$v^{2} = u^{2} + 2 a s$
$v^{2} = 0^{2} + (2 \times 0.5 \times 25) = 25$
$∴ v = 5 m s^{- 1}$

Suggest Corrections

Similar questions

Q. A car initially at rest starts moving with a constant acceleration of

0.5 m s^{- 2}

and travels a distance of

25 m

. Find the time taken.

Q. A car travels a distance

100 m

with a constant acceleration and average velocity of

20 m s^{- 1}

. The final velocity acquired by the car is

25 m s^{- 1}

. Find the initial velocity.

Q. A body initially moving with a velocity of

5 {ms}^{- 1}

, attains a velocity of

25 {ms}^{- 1}

5 s

. The acceleration of the body is:
(Assume constant acceleration)

A car travels a distance 100 m with a constant acceleration and average velocity of 20 $m s^{- 1}$ .The final velocity acquired by the car is 25 $m s^{- 1}$ .Find:(i) the initial velocity and (ii) acceleration of car.

Q. Consider a particle initially moving with a velocity of

5 m s^{- 1}

starts decelerating at a constant rate of

2 m s^{- 2}

. Find the distance travelled in the second second.

Join BYJU'S Learning Program

A car initially at rest starts moving with a constant acceleration of 0.5ms−2 and travels a distance of 25m. Find the final velocity.

The correct option is B 5ms−1Given,u=0a=0.5ms−2s=25mv2=u2+2asv2=02+(2×0.5×25)=25∴v=5ms−1

A car initially at rest starts moving with a constant acceleration of $0.5 m s^{- 2}$ and travels a distance of $25 m$ . Find the final velocity.

The correct option is B $5 m s^{- 1}$
Given,
$u = 0$
$a = 0.5 m s^{- 2}$
$s = 25 m$

$v^{2} = u^{2} + 2 a s$
$v^{2} = 0^{2} + (2 \times 0.5 \times 25) = 25$
$∴ v = 5 m s^{- 1}$