A car initially at rest starts moving with a constant acceleration of $0.5 m s^{- 2}$ and travels a distance of 25 m. The time taken is equal to:

1 s

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5 s

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10 s

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20 s

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Solution

The correct option is D 10 s
$s = u t + (1 / 2) a t^{2}$
$25 = (1 / 2) \times 0.5 \times t^{2}$
$t = 10 s$

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A car initially at rest starts moving with a constant acceleration of 0.5ms−2 and travels a distance of 25 m. The time taken is equal to:

The correct option is D 10 ss=ut+(1/2)at225=(1/2)×0.5×t2t=10 s

A car initially at rest starts moving with a constant acceleration of $0.5 m s^{- 2}$ and travels a distance of 25 m. The time taken is equal to:

The correct option is D 10 s
$s = u t + (1 / 2) a t^{2}$
$25 = (1 / 2) \times 0.5 \times t^{2}$
$t = 10 s$