a car is being driven at a speed of 20 MS power -1 when brakes are applied to bring it to rest in 5 seconds the acceleration produced in this case will be what

Open in App

Solution

Dear Student
$I n i t i a l s p e e d = 20 m s^{- 1} t i m e = 5 s e c F i n a l s p e e d = 0 v = u - a t (- s i g n b e c a u s e t h e v e l o c i t y i s d e c r e a \sin g) u = a t a = 20 / 5 = 4 m s^{- 2} R E G A R D S$

Suggest Corrections

Similar questions

A motorcycle is being driven at a speed of 20 m/s when brakes are applied to bring it to rest in five seconds. The deceleration produced in this case will be :

(a) $+ 4 m s^{2}$

(b) $- 4 m s^{2}$

(d) $- 0.25 m s^{2}$

A car is being driven at a speed of 20m/sec when brakes are applied to bring it to rest in 5sec. The declaration produced in this case will be??

Answer is -4 m/sec square

Teacher plz explain the evaluation

Q. When a car driver travelling at a speed of

20 m/s

applies the brakes and brings the car to rest in

4 sec

, the acceleration of car will be :

Q. When brakes are applied the velocity of a car changes from

{30 m s}^{- 1} t o {10 m s}^{- 1}

in 5 s. The acceleration produced in it is ____

{m s}^{- 2}

Q. When a bus driver travelling at a speed of 20m/s applied brakes and brings the bus to rest in 10 seconds, then retardation will be

Join BYJU'S Learning Program

a car is being driven at a speed of 20 MS power -1 when brakes are applied to bring it to rest in 5 seconds the acceleration produced in this case will be what

Dear Student Initial speed=20ms-1time=5secFinal speed=0v=u-at (- sign because the velocity is decreasing)u=ata=20/5=4ms-2REGARDS

Dear Student
$I n i t i a l s p e e d = 20 m s^{- 1} t i m e = 5 s e c F i n a l s p e e d = 0 v = u - a t (- s i g n b e c a u s e t h e v e l o c i t y i s d e c r e a \sin g) u = a t a = 20 / 5 = 4 m s^{- 2} R E G A R D S$