A car is moving along a straight line- It-s displacement x - time t graph is shown- Match the entries in column I with points on graph as in Column-II- Column Ip x - negative-v - positive-a - positive q x - positive- v - negative-a - negativer x - negative-v - negative-a - positive s x - positive- v - positive-a - negative- Column II

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Acceleration

A car is movi...

Question

A car is moving along a straight line. It's displacement (x) - time (t) graph is shown. Match the entries in column I with points on graph as in Column-II.

Column I

(p) x $\to$ negative,v $\to$ positive,a $\to$ positive (q) x $\to$ positive, v $\to$ negative,a $\to$ negative

(r) x $\to$ negative,v $\to$ negative,a $\to$ positive (s) x $\to$ positive, v $\to$ positive,a $\to$ negative.

Column II

(p - d) (q - b) (r - c) (s - a)

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(p - b) (q - d) (r - c) (s - a)

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(p - a) (q - c) (r - b) (s - d)

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(p - c) (q - a) (r - d) (s - b)

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Solution

The correct option is A
(p - d) (q - b) (r - c) (s - a)

At,A,x is positive,

v is positive as the the slope is positive

a is negative as the slope is decreasing

At,B,x is positive,

v is positive as the the slope is negative

a is negative as the slope is still decrease

At C,x is negative, At D, x is negative

v is negative v is positive

a is positive a is positive

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A car is moving along a straight line. It's displacement (x) - time (t) graph is shown. Match the entries in column I with points on graph as in Column-II.

Column I

(p) x $\to$ negative,v $\to$ positive,a $\to$ positive (q) x $\to$ positive, v $\to$ negative,a $\to$ negative

(r) x $\to$ negative,v $\to$ negative,a $\to$ positive (s) x $\to$ positive, v $\to$ positive,a $\to$ negative.

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