Question

A car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 m/sec. A plumb bob is suspended from the roof of the car by a light rigid rod of length 1.00 m. The angle made by the rod with the vertical is

• A. Zero
• B.
• C.
• D.

Answer 1

The correct option is C.

We know that,

$tan\theta =\frac{\frac{v^2}{r}}{g}=\frac{v^2}{rg}$

$\therefore \theta =ta{n}^{-1}\left(\frac{v^2}{rg}\right)=ta{n}^{-1}\left(\frac{10\times 10}{10\times 10}\right)$

$\therefore \theta =ta{n}^{-1}\left(1\right)={45}^{\circ }$.

Thus the angle made by the rod with the vertical is ${45}^{\circ }$.