A car is moving in a straight line with speed $18 k m h^{- 1}$ . It is stopped in $5 s$ by applying the brakes. Find the retardation.

3.6 m s^{- 2}

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- 3.6 m s^{- 2}

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- 1 m s^{- 2}

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2 m s^{- 2}

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Solution

The correct option is B $- 1 m s^{- 2}$
Initial Velocity, $v_{i} = 18 k m / h = 5 m / s$
Final Velocity, $v_{f} = 0 m / s$
Change in velocity, $Δ v = v_{f} - v_{i} = 0 m / s - 5 m / s = - 5 m / s$
Therefore, $R e t a r d a t i o n = \frac{Δ v}{t} = \frac{- 5 m / s}{5 s} = - 1 m / s^{2}$

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Similar questions

A car is moving in a straight line with speed 18 km $h^{- 1}$ . It is stopped in 5 s by applying the brakes. Find:

(i) the speed of car in m $s^{- 1}$ ,
(ii) the retardation of car
(iii) the speed of car after 2 s of applying the brakes.

18 k m h^{- 1}

5 s

18 k m p h

5 s

m s^{- 1}

2 m s^{- 1}

0.5 m s^{- 2}

A car is retarded by applying brakes at the rate of 2 m/ $s^{2}$ It is finally stopped in 10 s. Find its initial velocity.

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