A car is moving in uniform velocity of 36 $\frac{k m}{h r}$ . What is the kinetic energy of the object kept in car. The mass of the object is 20 kg.

1000 J

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2000 J

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3000 J

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4000 J

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Solution

The correct option is A
1000 J

Kinetic energy (KE) = $\frac{1}{2}$ m $v^{2}$

Velocity = 36 $\frac{k m}{h r}$

= 36 * $\frac{5}{18}$ = 10 $\frac{m}{s}$

Kinetic energy = 20 * $\frac{10^{2}}{2}$

= 1000 J

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What is the work done (in KJ) to increase the velocity of a car from 36 $\frac{k m}{h r}$ to 90 $\frac{k m}{h r}$ ? When the weight of the car is 1000 kg.

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A car is moving in uniform velocity of 36 kmhr. What is the kinetic energy of the object kept in car. The mass of the object is 20 kg.

The correct option is A 1000 J Kinetic energy (KE) = 12 m v2 Velocity = 36 kmhr = 36 * 518 = 10 ms Kinetic energy = 20 * 1022 = 1000 J

A car is moving in uniform velocity of 36 $\frac{k m}{h r}$ . What is the kinetic energy of the object kept in car. The mass of the object is 20 kg.

The correct option is A
1000 J

Kinetic energy (KE) = $\frac{1}{2}$ m $v^{2}$

Velocity = 36 $\frac{k m}{h r}$

= 36 * $\frac{5}{18}$ = 10 $\frac{m}{s}$

Kinetic energy = 20 * $\frac{10^{2}}{2}$

= 1000 J