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Uniform Circular Motion

A car is movi...

Question

A car is moving on a circular path and takes a turn. If $R_{1}$ and $R_{2}$ be the reactions on the inner and outer wheels respectively, then

A

R_{1} = R_{2}

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B

R_{1} < R_{2}

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C

R_{1} > R_{2}

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D

R_{1} ⩾ R_{2}

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Solution

The correct option is B $R_{1} < R_{2}$
The weight Mg of the car acts vertically decreases through the center of gravity G of the car
$∴ R_{1} + R_{2} = M g$
and the horizontal force F provides the centripetal force for motion in a circle
$∴ F = \frac{m v^{2}}{r}$
Taking moments about G, there should be no resultant turning effect about the center of gravity
$F h + R_{1} a = R_{2} a ∴ R_{2} = \frac{F h + R_{1} a}{a} o r, R_{2} = R_{1} + (\frac{F h}{a}) \Rightarrow R_{2} > R_{1}$

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Similar questions

Q. A car is moving on a circular path and takes a turn. If

R_{1}

R_{2}

be the reactions on the inner and outer wheels respectively, then

Q. A car is moving on a circular path and takes a turn. if

R_{1}

R_{2}

, be the reactions on the inner and outer wheels respectively, then

Q. For the following reactions, the correct reaction rates

r_{1}, r_{2}, r_{1}^{'}

r_{2}^{'}

R_{1}

R_{2}

be two relations defined on a non empty set A. Which of the following statements is false? Give reasons in support of your answer.
(a) If

R_{1}

R_{2}

are reflexive, then so is

R_{1} \cap R_{2}

R_{1}

R_{2}

are symmetric, then so is

R_{1} \cup R_{2}

R_{1}

R_{2}

are transitive, then so is

R_{1} \cup R_{2}

R_{1}

R_{2}

are transitive, then so is

R_{1} \cap R_{2}

R_{1}

R_{2}

are symmetric, then so is

R_{1} \cap R_{2}

Q. Assertion :In a

△ A B C

a < b < c

r

is inradius and

r_{1}, r_{2}, r_{3}

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A, B, C

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r < r_{1} < r_{2} < r_{3}

△ A B C, r_{1} r_{2} + r_{2} r_{3} + r_{3} r_{1} = \frac{r_{1} r_{2} r_{3}}{r}

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