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Question

A car is moving on a circular path with a constant speed of 10 m/s. What is the magnitude of change in velocity when it moves through 120?

A
0
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B
103 m/s
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C
10 m/s
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D
102 m/s
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Solution

The correct option is B 103 m/s
Let the initial position and final position be A and B respectively.
Velocity at initial point A = vA
Velocity at final point B = vB
Angle between vA and vB is θ=1200
Change in velocity
Δv=|vBvA|=v2B+v2A2vBvAcosθ
Since speed is constant vA=vB=v=10 m/s
Δv=2v2×1cosθ=v2×2sin2θ2Δv=2vsinθ2=2×10×sin 600Δv=103 m/s

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