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Question

A car is moving on a circular road of radius of curvature 500 m. If the coefficient of friction is 0.8 and g=10 m/s2, the maximum speed of the car can have without slipping is in (km/hr).

A
510
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B
2010
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C
7210
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D
5410
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Solution

The correct option is C 7210
Given, radius of curvature (r)=500 m
Coefficient of friction (μ)=0.8

Condition for max speed of the car for not slipping is,

μmg=mv2maxr, here the frictional force will provide the necessary centripetal force
(vmax)=μrg=0.8×500×10=45×500×10
=4×100×10
=2010 m/s or 7210 km/hr
(As to convert (m/s) to (km/hr) we multiply it by 185)

Hence option C is the correct answer

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