A car is moving on a levelled circular road of radius of curvature 300m. If the coefficient of static friction is 0.3 and acceleration due to gravity is 10ms−2, then maximum allowable speed for the car will be (in kmh−1)
A
30
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B
81
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C
108
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D
162
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Solution
The correct option is C108 To avoid slipping, frictional force will act in a direction to provide the necessary centripetal force. i.e frictional force will act towards centre of circular curvature.
Here, f is magnitude of frictional force. ∴f=mv2maxr ∴μsmg=mv2maxr
Here, it is given that r=300m,μs=0.3,g=10ms−2
Applying the formula, vmax=√μsrg=√0.3×300×10=30ms−1
Or, 30×185kmh−1=108kmh−1