A car is moving towards a person. the person observes a change of 2.5% in the frequency of its horn. If the velocity of sound is 320 ms−1, then the velocity of the car is :
A
6 ms−1
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B
8 ms−1
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C
7.5 ms−1
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D
800 ms−1
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Solution
The correct option is D 8 ms−1 Let the original frequency of the car be fo. Since the car is moving towards the stationary observer, so the apparent frequency heard by the observer is greater than original frequency. Apparent frequency heard f=1.025fo Using Doppler effect, f=fo[VsoundVsound−Vcar] ∴1.025fo=fo[320320−Vcar] ⟹Vcar=8m/s