A car is moving with a speed of 30 ms−1 on a circular path of radius 500m. Its speed is increasing at the rate of 2 ms−2. The acceleration of the car at that moment is :
A
2.7 ms−2
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B
9.8 ms−2
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C
2 ms−2
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D
1.8 ms−2
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Solution
The correct option is A 2.7 ms−2
at=2ms−2 and ac=v2r=(30)2500=95ms−2=1.8ms−2
net acceleration a=√(at)2+(ac)2=√(2)2+(1.8)2=√7.24=2.69ms−2≈2.7ms−2