a car is moving with a velocity of 180 kmph antiques 6 seconds to stop after the brakes are applied .calculate the force exerted by the brakes if mass is 500 kgs

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Solution

U = 180 km/h
=> 180×5/18
=>50 m/s
v = 0m/s
t = 6sec
therefore , a = (v-u)/t
=>a = (0-50)/6
=> a = -50/6 => -8.33 m/s²

force = mass × acceleration
force = 500 kg × (-8.33) m/s²
force = -4165 kg m/s²
=> force = -4165 N

negative sign denotes opposing force

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a car is moving with a velocity of 180 kmph antiques 6 seconds to stop after the brakes are applied .calculate the force exerted by the brakes if mass is 500 kgs

U = 180 km/h => 180×5/18 =>50 m/s v = 0m/s t = 6sec therefore , a = (v-u)/t =>a = (0-50)/6 => a = -50/6 => -8.33 m/s² force = mass × acceleration force = 500 kg × (-8.33) m/s² force = -4165 kg m/s² => force = -4165 N negative sign denotes opposing force

U = 180 km/h
=> 180×5/18
=>50 m/s
v = 0m/s
t = 6sec
therefore , a = (v-u)/t
=>a = (0-50)/6
=> a = -50/6 => -8.33 m/s²

force = mass × acceleration
force = 500 kg × (-8.33) m/s²
force = -4165 kg m/s²
=> force = -4165 N

negative sign denotes opposing force