Question

A car is moving with initial velocity $u=3\text{m/s}$ and acceleration $a=2m/s^2$ then, the displacement of car in $6^{th}$ second is

• A. $8\text{m}$
• B. $14\text{m}$
• C. $10\text{m}$
• D. $12\text{m}$

Answer 1

The correct option is B $14\text{m}$

Given, $u=3\text{m/s},a=2{\text{m/s}}^2$
As we know that the distance travelled by a particle in $n^{th}$ second is given as
$S_n=u+\frac{1}{2}a(2n-1)$
$S_{6^{th}}=3+\frac{1}{2}\times 2(2\times 6-1)=3+11=14\text{m}$