wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A car is moving with speed 27 km/h. The driver applies brakes as he approaches a circular turn on the road of radius 80 m and his speed reduce at the constant rate of 0.50 m/s every second. The magnitude of net acceleration is:

A
20ms2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
250ms2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
100ms2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D None of these

Speed of cyclist=27km/h

=27×10003600

=7.5m/s

Radius of track =80m

Centripetal acceleration a=v2r

ac=(7.5)2/80=0.7m/s2

Tangential acceleration at=0.5m/s2

Net acceleration

a=at2+at2=(0.5)2+(0.7)2=0.8m/s2


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Centripetal Force and Circular Motion Tackle
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon