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Question

A car is moving with speed 27 km/h. The driver applies brakes as he approaches a circular turn on the road of radius 80 m and his speed reduce at the constant rate of 0.50 m/s every second. The magnitude of net acceleration is:

A
20ms2
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B
250ms2
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C
100ms2
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D
None of these
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Solution

The correct option is D None of these

Speed of cyclist=27km/h

=27×10003600

=7.5m/s

Radius of track =80m

Centripetal acceleration a=v2r

ac=(7.5)2/80=0.7m/s2

Tangential acceleration at=0.5m/s2

Net acceleration

a=at2+at2=(0.5)2+(0.7)2=0.8m/s2


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