Question

A car is travelling with speed v on a circular road of radius r. If it is increasing its speed at the rate of 'a' meter/sec², then the resultant acceleration will be

• A. $\sqrt{\{\frac{v^2}{r^2}-a^2\}}$
• B. $\sqrt{\{\frac{v^4}{r^2}+a^2\}}$
• C. $\sqrt{\{\frac{v^4}{r^2}-a^2\}}$
• D. $\sqrt{\{\frac{v^2}{r^2}+a^2\}}$

Answer 1

The correct option is B

$\sqrt{\{\frac{v^4}{r^2}+a^2\}}$

$a_{resultant}$=$\sqrt{a_{radial}^2+a_{tangential}^2}=\sqrt{\frac{v^4}{r^2}+a^2}$