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Question

A car made a run of 390 km in `x` hours. If the speed had been 4 km/hour more, it would have taken 2 hours less for the journey. Find `x`.

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Solution

Let the actual speed be v km/hour
actual speed of run,v = distance/time = 390 over x km/hour
if this speed is increased by 4 km/hour, time will be 2 hours less
i.e

390 over v minus open square brackets fraction numerator 390 over denominator space v plus 4 end fraction close square brackets equals 2 fraction numerator 390 left parenthesis v plus 4 right parenthesis minus 390 v over denominator v left parenthesis v plus 4 right parenthesis end fraction equals 2

780=v2+4v

v2+4v780=0

v2+30v26v780=0

v(v+30)26(v+30)=0

(v+30)(v26)=0

so, v= 26 km/hours ,

neglecting negative value

so, time, x=39026=15hours


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