Question

A car moves 30 km in 0.5 h and the next 30 km in $\frac{2}{3}h$.Calculate the average speed for the entire trip in $\frac{m}{s}$.

Answer 1

Step 1:

Given that

Time to travel first 30 km is $t_1$ = 0.5 h.

Time to travel next 30 km is $t_2$=$\frac{2}{3}h$.

Step 2:

Total time ,$t=t_1+t_2$.

Average speed =$\frac{Totaldis\tan ce}{totaltime}$.

Step 3:

Total time ,$t=t_1+t_2$.

Total time = $0.5h+\frac{2}{3}h=\frac{3.5}{3}h=1.167h$.

Total distance =d=30 km +30 km = 60 km.

Average speed =$\frac{Totaldis\tan ce}{totaltime}$.

V= $\frac{60}{1.167}$= $51.42\frac{km}{h}$

Speed in $\frac{m}{s}$ = V$\times \frac{5m}{18s}$

V =$51.42\times \frac{5m}{18s}.$

V = $14.29\frac{m}{s}$.

Step 4:

Hence, The average speed for the entire trip will be $14.29\frac{m}{s}$.