CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A car moves along a straight line whose equation of motion is given by s=12t+t2−2t3, where distance is in meters and time is in seconds. The velocity of the car to start will be

A
7 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
9 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
12 m/s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
16 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Join BYJU'S Learning Program
CrossIcon