A car moves along the periphery of a square field of side 10 meters. He completes travelling one side in 40 seconds. What will be the magnitude of distance and displacement at the end of 2min and 20 seconds ?

35m, 35m

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35m, 5m

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25m, 10m

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35m, 10m

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Solution

The correct option is B
35m, 5m

Distance = speed $\times$ time
= $\frac{10}{40}$ $\times$ 140
= 35m

Finding distance between initial and final position to find out displacement.
In travelling 35m around of a square of perimeter 40m, the body is 5m off its initial position.
So, its displacement will be 5m.

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A car moves along the periphery of a square field of side 10 meters. He completes travelling one side in 40 seconds. What will be the magnitude of distance and displacement at the end of 2min and 20 seconds ?

The correct option is B 35m, 5m Distance = speed × time = 1040×140 = 35m Finding distance between initial and final position to find out displacement. In travelling 35m around of a square of perimeter 40m, the body is 5m off its initial position. So, its displacement will be 5m.