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Question
A car moves along the periphery of a square field of side 10m. He completes traveling one side in 40s. What will be the magnitude of distance and displacement at the end of 2min and 20 seconds?
A car moves along the periphery of a square field of side 10m. He completes traveling one side in 40s. What will be the magnitude of distance and displacement at the end of 2min and 20 seconds?
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Solution
The correct option is B 35m, 5m
It is given that the car travels at a speed of 1040m/s.
Total distance covered after 2min 20s (i.e., 140s) will be:
Distance = Speed × Time
= 1040×140
= 35 meters
Displacement will be the difference between the initial and final points.
If the car covers 35 meters in 140s along the perimeter of a square, it means that the car has traveled 10 meters along the first three sides and 5 meters along the fourth side. It is 5 meters short of reaching the initial point.
Therefore, the displacement will 5 meters.
35m, 5m
It is given that the car travels at a speed of 1040m/s.
Total distance covered after 2min 20s (i.e., 140s) will be:
Distance = Speed × Time
= 1040×140
= 35 meters
Displacement will be the difference between the initial and final points.
If the car covers 35 meters in 140s along the perimeter of a square, it means that the car has traveled 10 meters along the first three sides and 5 meters along the fourth side. It is 5 meters short of reaching the initial point.
Therefore, the displacement will 5 meters.
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