A car moves with a speed of $10 m/s$ for $0.5$ hours and then with a speed of $60 km/h$ for the next $15$ minutes. The total distance covered by the car is:

50 km

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100 km

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66 km

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33 km

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Solution

The correct option is D $33 km$

Let

Distance covered by the car in the first $0.5$ hours with a speed of $45 km/h$ be L1 $= 10 m/s \times 0.5 hrs$

To convert the speed unit from m/s into km/h we have to multiply with 3.6

L1 $= 10 \times 3.6 \times 0.5 = 18 km$

Let

Distance covered by the car in last $15$ minutes with a speed of $55 km/h$ be L2. $= 60 km/h \times 15 min$ .

To convert the time unit from minutes into hours we have to divide by 60

L2 $= 60 \times (\frac{15}{60}) = 15 km$

Total distance covered = L1 + L2 = $18 + 15 = 33 km$

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