A car moving at 10 $m s^{- 1}$ is to be brought to rest within 15 seconds. What is the magnitude of force required to achieve this? Take mass of car to be $180 k g$ .

100 N

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110 N

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120 N

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150 N

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Solution

The correct option is C $120 N$
Given: initial velocity of car $u = 10 m s^{- 1}$ , final velocity of car $v = 0 m s^{- 1}$ , mass of car $m = 180 k g$ , time taken for the car to stop $t = 15 s e c o n d s$ .
Let the force needed to stop the car is $F$
Using newtons second law of motion: $F = m \times \frac{v - u}{t} = 180 \times \frac{0 - 10}{15} = - 120 N$
So, magnitude of force is 120 N

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