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1st Equation of Motion

A car moving ...

Question

A car moving at a speed of $20 m / s$ is slowed down to a speed of $10 m / s$ over a distance of $30 m$ . What is the retardation produced during this time and what is the time taken?

5 m / s^{2}

and

5 s

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4 m / s^{2}

and

2 s

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5 m / s^{2}

and

2 s

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4 m / s^{2}

and

5 s

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Solution

The correct option is C $5 m / s^{2}$ and $2 s$
We have,
$u = 20 m / s v = 10 m / s s = 30 m$

We know:
$v^{2} = u^{2} + 2 a s \Rightarrow 100 = 400 + 2 \times a \times 30 \Rightarrow a = - 5 m / s^{2}$
The negative sign indicates that the body is slowing down.
Also, $v = u +$ at $\Rightarrow 10 = 20 - 5 t \Rightarrow t = 2 s$

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A car moving at a speed of 20 m/s is slowed down to a speed of 10 m/s over a distance of 30 m. What is the retardation produced during this time and what is the time taken?

The correct option is C 5 m/s2 and 2 sWe have, u=20 m/sv=10 m/ss=30 m We know: v2=u2+2as⇒100=400+2×a×30⇒a=−5 m/s2 The negative sign indicates that the body is slowing down. Also, v=u+ at ⇒10=20−5t⇒t=2s

A car moving at a speed of $20 m / s$ is slowed down to a speed of $10 m / s$ over a distance of $30 m$ . What is the retardation produced during this time and what is the time taken?