A car moving at a speed v is stopped in a certain distance when the brakes produce a deceleration a . If the speed of the car was nv , what must be the deceleration of the car to stop it in the same distance and in the same time?
The deceleration of the car is given as,
a=v22s
If the speed of the car was nv then the new deceleration is given as,
a′=(nv)22s
=n2v22s
=n2a
Thus, the new deceleration of the car is n2a.