A car moving on a straight road covers $\frac{1}{3} rd$ of the total distance with speed $40$ km/h and remaining distance with speed $60$ km/h. Average speed of the car for total distance is

48.7

km/h

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51.4

km/h

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58

km/h

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72

km/h

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Solution

The correct option is B $51.4$ km/h
Answer (3)
$Average speed V_{a v g} = \frac{Total distance}{total times}$
$= \frac{d}{\frac{d}{3 \times 40} + \frac{2 d}{3 \times 60}}$
= 51.4 km/h

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