A car moving on a straight road covers the one third of the total distance with 20 Km / h and the rest with 60 Km /h .The average speed is

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Solution

$\begin{matrix} a v e r a g e s p e e d = \frac{T o t a l d i s t . c o v e r}{T o t a l t i m e t a k e n} = \frac{d}{\frac{d}{3.20} + \frac{2 d}{3.6.}} = \frac{1}{\frac{3}{180} + \frac{2}{180}} = 36 k m / h \end{matrix}$

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A car moving on a straight road covers one third of the distance with 20 km/hr and the rest with 60 km/hr. The average speed is

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