Question

# A car moving with a speed of $$180\ km/h$$ to rest after $$4s$$ on applying brake, if the mass of the car including the passengers is $$1000\ kg$$, what will be the force applied when brake is applied?

Solution

## Initial velocity of the car $$u=108\ km/h$$$$=108 \times \dfrac{1000}{60 \times 60}$$$$=108 \times \dfrac{5}{18}$$$$=30\ m/s$$Final velocity $$v=0$$Mass $$m=1000\ kg$$Time $$t=4s$$According to newton's second law$$F=ma$$$$F=m \dfrac{(v-u)}{t}$$$$=\dfrac{1000(0-30)}{4}$$$$=- 7500\ N$$The negative sign indicates that the applied force is opposite to the direction of motion.Physics

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