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Question

A car moving with a speed of $$180\ km/h$$ to rest after $$4s$$ on applying brake, if the mass of the car including the passengers is $$1000\ kg$$, what will be the force applied when brake is applied?


Solution

Initial velocity of the car $$u=108\ km/h$$
$$=108 \times \dfrac{1000}{60 \times 60}$$

$$=108 \times \dfrac{5}{18}$$
$$=30\ m/s$$
Final velocity $$v=0$$
Mass $$m=1000\ kg$$
Time $$t=4s$$

According to newton's second law
$$F=ma$$
$$F=m \dfrac{(v-u)}{t}$$
$$=\dfrac{1000(0-30)}{4}$$
$$=- 7500\ N$$
The negative sign indicates that the applied force is opposite to the direction of motion.

Physics

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