A car moving with a speed of $180 k m / h$ to rest after $4 s$ on applying brake, if the mass of the car including the passengers is $1000 k g$ , what will be the force applied when brake is applied?

Open in App

Solution

Initial velocity of the car $u = 108 k m / h$
$= 108 \times \frac{1000}{60 \times 60}$

$= 108 \times \frac{5}{18}$
$= 30 m / s$
Final velocity $v = 0$
Mass $m = 1000 k g$
Time $t = 4 s$

According to newton's second law
$F = m a$
$F = m \frac{(v - u)}{t}$
$= \frac{1000 (0 - 30)}{4}$
$= - 7500 N$
The negative sign indicates that the applied force is opposite to the direction of motion.

Suggest Corrections

Similar questions

A motorcycle is moving with a velocity of 108km/h and it takes 4s to stop after brakes are applied. Calculate the force exerted by the brakes on the car when mass is 1000kg.

Q. A car of mass

1000 kg

moving with a velocity of

20 m/s

is brought to rest by applying brakes in

10 seconds

. What is the force applied by the brakes?

Q. A car is moving with velocity of 16 m second when brakes are applied the force applied by the brakes is 1000 n the mass of the car is a passengers is 1200 kilogram. (a) how long should the brakes be applied to make the car come to a halt? (B) how far does the car travel before it comes to rest?

Q. A motorcar is moving with a velocity of

108 k m / h

and it takes

4 s

to stop after the brakes are applied. Calculate the force exerted by the brakes on the motorcar if its mass along with the passengers is

1000 k g .

a car moving with a speed of 8 km/h stops in 4 seconds when the brakes are applied.how much force is applied by the brakes on the car if the weight of the car with its passengers is 800 kg

Join BYJU'S Learning Program

A car moving with a speed of 180 km/h to rest after 4s on applying brake, if the mass of the car including the passengers is 1000 kg, what will be the force applied when brake is applied?

Initial velocity of the car u=108 km/h=108×100060×60=108×518=30 m/sFinal velocity v=0Mass m=1000 kgTime t=4sAccording to newton's second lawF=maF=m(v−u)t=1000(0−30)4=−7500 NThe negative sign indicates that the applied force is opposite to the direction of motion.

A car moving with a speed of $180 k m / h$ to rest after $4 s$ on applying brake, if the mass of the car including the passengers is $1000 k g$ , what will be the force applied when brake is applied?