A car moving with a speed of 40 km/h can be stopped by applying brakes at least after 2m. If the same car is moving with a speed of 80 km/h, what is the minimum stopping distance?

8 c m

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6 m

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4 m

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2.6 m

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Solution

The correct option is C $2.6 m$
Speed is $u = \frac{40 \times 5}{18} m / s = \frac{100}{9} m / s$
We need to stop it in $120 s e c$ so acceleration $a = \frac{u}{t} = \frac{100}{9 \times 120}$
Minimum stopping distance will be $s = \frac{v^{2}}{2 a} = \frac{(80 \times 5 / 18)^{2}}{2 \times 100 / 1080} = 2666.6 m = 2.66 k m$

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